Which of the following pairs has both the ion | vedclass

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(D) Ions are coloured in aqueous solution if they have unpaired electrons in their $d$-orbitals (i.e.,$d^1$ to $d^9$ configuration).$1$. $Sc^{3+}$ $(3

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$Mn^{2+}, Ti^{3+}$

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(D) Ions are coloured in aqueous solution if they have unpaired electrons in their $d$-orbitals (i.e.,$d^1$ to $d^9$ configuration).$1$. $Sc^{3+}$ $(3d^0)$: Colourless (no unpaired electrons).$2$. $Ti^{3+}$ $(3d^1)$: Coloured (one unpaired electron).$3$. $Mn^{2+}$ $(3d^5)$: Coloured (five unpaired electrons).$4$. $Ni^{2+}$ $(3d^8)$: Coloured (two unpaired electrons).$5$. $Cu^{+}$ $(3d^{10})$: Colourless (no unpaired electrons).$6$. $Ti^{4+}$ $(3d^0)$: Colourless (no unpaired electrons).Comparing the options:- Option $(A)$: $Sc^{3+}$ is colourless.- Option $(B)$: $Ti^{4+}$ is colourless.- Option $(C)$: $Cu^{+}$ is colourless.- Option $(D)$: Both $Mn^{2+}$ and $Ti^{3+}$ have unpaired electrons and are coloured.Therefore,the correct pair is $(Mn^{2+}, Ti^{3+})$.

$I. \ Zn^{2+}$	$(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$	$(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$	$(iii) \ \mu = 1.73 \ \text{BM}$

Which of the following pairs has both the ions coloured in aqueous solution? [Atomic numbers of $Sc=21, Ti=22, Ni=28, Cu=29, Mn=25$]

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Match the following:
$I. \ Zn^{2+}$ $(i) \ d^8 \ \text{configuration}$
$II. \ Cu^{2+}$ $(ii) \ \text{Colourless}$
$III. \ Ni^{2+}$ $(iii) \ \mu = 1.73 \ \text{BM}$

The aqueous solution of which of the following ion is colourless?

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